Lesson 3 · Parallelism

Section 03

Proving that two straight lines are parallel

Two straight lines cut by a transversal are parallel whenever one of three conditions holds. Combine a condition with a clean, justified write-up and the proof is complete.

The three conditions

1

Two corresponding angles are equal in measure.

2

Two alternating angles (both interior or both exterior) are equal in measure.

3

Two interior angles on the same side of the transversal are supplementary.

Also useful: if two straight lines are parallel to a third line, they are parallel to each other. If a straight line is perpendicular to one of two parallel lines, it is perpendicular to the other. Two lines perpendicular to the same line in a plane are parallel.

How to write a proof in geometry

  1. Step 1

    Read carefully

    Separate what is given from what is required. Every word in the statement is data.

  2. Step 2

    Write the given

    List the given facts as short bullet points, using symbols (∥, ⊥, m(∠A) = …).

  3. Step 3

    Write the required

    State exactly what must be found or proved.

  4. Step 4

    Plan the proof

    Sketch the essential steps that connect the given to the required before writing.

  5. Step 5

    Write statements + reasons

    Each mathematical statement needs a justification: a definition, postulate, theorem, given fact or property.

  6. Step 6

    Check

    Confirm the required question is answered and the numbers are consistent.

Notation: the symbol ∵ is short for “since” and introduces a given fact or theorem; ∴ is short for “therefore” and introduces a derived statement.

Worked proofs

Example 2 — find x and y

Given

  • CD ∥ BA
  • BC ∥ DE
  • m(∠ABC) = 70°
  • m(∠CDE) = (x + 10)°
  • y = m(∠BCD)

Required

Find the values of x and y.

Proof

∵ BA ∥ CD and BC is a transversal
∴ m(∠ABC) = m(∠BCD) = 70°alternating interior angles are equal
∴ y = 70
∵ BC ∥ DE and CD is a transversal
∴ m(∠CDE) + m(∠BCD) = 180°interior angles on the same side are supplementary
∴ m(∠CDE) = 180° − 70° = 110°
∴ x + 10 = 110 ⟹ x = 100

Example 3a — prove BA ∥ CD

Given

  • m(∠ABC) = 58°
  • m(∠ECD) = 29°
  • CE bisects ∠BCD

Required

Prove that BA ∥ CD.

Proof

∵ CE bisects ∠BCD
∴ m(∠BCD) = 2 × 29° = 58°definition of an angle bisector
∵ m(∠ABC) = m(∠BCD) = 58°and they are alternating interior angles
∴ BA ∥ CDequal alternating interior angles

Example 3b — prove AB ∥ CD

Given

  • m(∠EFB) = 54°
  • m(∠CMF) = 126°

Required

Prove that AB ∥ CD.

Proof

∵ AB ∩ EN = {F}
∴ m(∠EFB) = m(∠AFM) = 54°vertically opposite angles
∵ m(∠AFM) + m(∠CMF) = 54° + 126° = 180°and they are interior angles on the same side
∴ AB ∥ CDco-interior angles are supplementary

Example 4 — the auxiliary parallel line

Given

  • DE ∥ BA
  • m(∠EDC) = 120°
  • m(∠ABC) = 130°

Required

Find m(∠DCB) with proof.

Proof

Construction: draw CF ∥ DE and ∥ BA through Ctwo lines parallel to a third are parallel
∵ DE ∥ CF and DC is a transversal
∴ m(∠DCF) = 180° − 120° = 60°interior angles on the same side
∵ BA ∥ CF and BC is a transversal
∴ m(∠BCF) = 180° − 130° = 50°interior angles on the same side
∴ m(∠DCB) = 60° + 50° = 110°angle addition
DCBDEBA120°130°auxiliary ∥ line